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Complementary Trigonometric Ratios

Question 4 i ...

Question

Question 4 (i)
Choose the correct option. Justify your choice.
(i) $9 s e c^{2} A - 9 t a n^{2} A =$
(A) 1
(B) 9
(C) 8
(D) 0

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Solution

(i) (B) is correct.
$9 s e c^{2} A - 9 t a n^{2} A$
$= 9 (s e c^{2} A - t a n^{2} A)$
$= 9 \times 1 = 9$ $(∵ s e c^{2} A - t a n^{2} A = 1)$

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Similar questions

Q. Question 4 (i)
Choose the correct option. Justify your choice.
(i)

9 s e c^{2} A - 9 t a n^{2} A =

(A) 1
(B) 9
(C) 8
(D) 0

Choose the correct option. Justify your choice.

(i) $9 {sec}^{2} A - 9 {tan}^{2} A =$

(A) $1$

(B) $9$

(C) $8$

(D) $0$

(ii) $(1 + tan θ + sec θ) (1 + cot θ - cosec θ)$

(A) $0$

(B) $1$

(C) $2$

(D) $- 1$

(iii) $(sec A + tan A) (1 - sin A) =$

(A) $sec A$

(B) $sin A$

(C) $cosec A$

(D) $cos A$

(iv) $\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A} =$

(A) ${sec}^{2} A$

(B) $- 1$

(C) ${cot}^{2} A$

(D) ${tan}^{2} A$

Q. Choose the correct option. Justify your choice.

9 {sec}^{2} A - 9 {tan}^{2} A =

Q. 9 sec² A − 9 tan² A is equal to

(a) 1
(b) 9
(c) 8
(d) 0

9 s e c^{2} A - 9 t a n^{2} A

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