(i) Potential difference, V = 6 V
1Ω and 2Ω resistors are connected in series.
Therefore, equivalent resistance of the circuit, R=1Ω +2Ω =3Ω
According to Ohm’s law, V = IR
Where, I is the current flowing through the circuit
I=63=2A
This current will flow through each component of the circuit because there is no division of current in series circuits.
Hence, current flowing through the 2Ω resistor is 2 A.
Power is given by the expression, P=(I)2R=(2)2×2=8W