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Question 14 (i)
Compare the power used in the 2Ω resistor in each of the following circuits:
(i) a 6 V battery in series with 1Ω and 2Ω resistors.

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Solution

(i) Potential difference, V = 6 V
1Ω and 2Ω resistors are connected in series.
Therefore, equivalent resistance of the circuit, R=1Ω +2Ω =3Ω
According to Ohm’s law, V = IR
Where, I is the current flowing through the circuit
I=63=2A
This current will flow through each component of the circuit because there is no division of current in series circuits.
Hence, current flowing through the 2Ω resistor is 2 A.
Power is given by the expression, P=(I)2R=(2)2×2=8W

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