I couldn't solve this sum of exponents

It asks to solve

3^{x square} : 3^x = 9+1

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Solution

3^{x square} : 3^x = 9+1
= 3^2x:3^x = 9+1
3^x:1 = 10
Taking log on both sides
ln3^x = ln10
x ln3 = ln10
x = ln10/ln3
x = 2.30259/1.0986
x = 2.09
You need the knowledge of logs to solve this question.

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I couldn't solve this sum of exponents It asks to solve 3x square : 3x = 9+1 ​​​​

3x square : 3x = 9+1 = 3^2x:3^x = 9+1 3^x:1 = 10 Taking log on both sides ln3^x = ln10 x ln3 = ln10 x = ln10/ln3 x = 2.30259/1.0986 x = 2.09 You need the knowledge of logs to solve this question.

I couldn't solve this sum of exponents

It asks to solve

3^{x square} : 3^x = 9+1

3^{x square} : 3^x = 9+1
= 3^2x:3^x = 9+1
3^x:1 = 10
Taking log on both sides
ln3^x = ln10
x ln3 = ln10
x = ln10/ln3
x = 2.30259/1.0986
x = 2.09
You need the knowledge of logs to solve this question.