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Question

I=xcosx+sinxxsinxdx Then I=?

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Solution

Consider the given integral.

I=xcosx+sinxxsinxdx

Let t=xsinx

dtdx=xcosx+sinx×1

dt=(xcosx+sinx)dx

Therefore,

I=1tdt

I=ln(t)+C

Thus,

I=ln(xsinx)+C

Hence, this is the answer.


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