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B
−12,−cotθ2
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C
−12,12cotθ2
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D
+12,cotθ2
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Solution
The correct option is A12,−12cotθ2 11−cosθ+isinθ =12sin2θ2+i2sinθ2cosθ2 =12sinθ2(1sinθ2+icosθ2) =12sinθ2(sinθ2−icosθ2) =12−icotθ22 =a+ib Hence a=12 and b=−12.cot(θ2)