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Arithmetic Mean and Range

i Earth Scien...

Question

Question 138 (i)

Earth Science
The table lists the world's 10 largest deserts.

What are the mean, median and mode of the areas listed ?

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Solution

Mean = $\frac{T o t a l a r e a o f a l l d e s e r t s}{N u m b e r o f d e s e r t s} = [\frac{8800000 + 1300000 + 1250000 + 850000 + 580000 + 370000 + 320000 + 310000 + 310000 + 260000}{10}] = \frac{14350000}{10} = 1435000 k m^{2} M e d i a n = \frac{(\frac{N}{2}) t h t e r m + (\frac{N}{2} + 1) t h t e r m}{2} = \frac{\frac{10}{2} t h t e r m + (\frac{10}{2} + 1) t h t e r m}{2} = \frac{5 t h t e r m + 6 t h t e r m}{2} = \frac{580000 + 370000}{2} = \frac{950000}{2} = 475000 k m^{2} [h e r e, N = 10] M o d e = M o s t f r e q u e n t o b s e r v a t i o n = 310000 k m^{2}$

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Question 138 (iv)

Earth Science
The table lists the world's 10 largest deserts.
What percentage of the total area of the deserts listed is in Asia?

Q. Question 3
Which measures of central tendency get affected if the extreme observations on both the ends of a data arranged in descending order are removed?
(a) Mean and mode
(b) Mean and median
(c) Mode and median
(d) Mean, median and mode

Q. For a frequency distribution, mean, median and mode are connected by the relation

(a) Mode = 3 Mean − 2 Median
(b) Mode = 2 Median − 3 Mean
(c) Mode = 3 Median − 2 Mean
(d) Mode = 3 Median + 2 Mean

Q. The relation between mean, mode and median is
(a) mode = (3 × mean) − (2 × median)
(b) mode = (3 × median) − (2 × mean)
(c) mode = (3 × mean) − (2 × mode)
(d) mode = (3 × median) − (2 × mode)

Q. The empirical relation between mean, mode and median is

(a) Mode = 3 Median − 2 Mean

(b) Mode = 2 Median − 3 Mean

(c) Median = 3 Mode − 2 Mean

(d) Mean = 3 Median − 2 Mode

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Arithmetic Mean and Range

Standard VII Mathematics

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