Question

(i) Evaluate:

$\left(a\right)(-2)\times (-3)\times (-4)$

$\left(b\right)2\times (-3)\times (-4)$

$\left(c\right)\frac{2}{6}\times (-3)\times \frac{4}{10}$


(ii) Use the sign of >, < or = in the box to make the statements true.

$\left(a\right)(-8)+(-4)\square (-8)+(-4)$

$\left(b\right)(-3)+7-\left(19\right)\square 15-8+(-9)$

$\left(c\right)23-41+11\square 23-41-11$ [3 MARKS]

Answer 1

Each part: 1.5 Marks

(i) Multiplication of even no. of negative integers gives a positive integer whereas multiple of odd no. of negative integers gives a negative integer.

(a) We have multiplication of three negative integers. So, the product will be negative integers.
$(-2)\times (-3)\times (-4)=6\times (-4)=(-24)$

(b) We have multiplication of two negative integers and one positive integer. So, the product will be positive integers.
$2\times (-3)\times (-4)=12\times 2=24$

(c) $\frac{2}{6}\times (-3)\times \frac{4}{10}$
$=\frac{1}{3}\times -3\times \frac{2}{5}$
$=\frac{-2}{5}$


(ii) (a) $-12<-4$

(b) $-15<-2$

(c) $-7>-29$