Question

Question 4(i)
Evaluate:

$\frac{8^{-1}\times 5^3}{2^{-4}}$

Answer 1

$\frac{8^{-1}\times 5^3}{2^{-4}}=\frac{(2^3{)}^{-1}\times 5^3}{2^{-4}}[\because (a^m{)}^n=a^{m\times n}]=\frac{2^{-3}\times 5^3}{2^{-4}}=2^{-3-(-4)}\times 5^3[\because a^m÷a^n=a^{m-n}]=2^{-3+4}\times 5^3=2\times 125=250$