Question 124 (i)
Evaluate the following, using distributive property. −39×99
−39×99=(−40+1)×(100−1)=−40×(100−1)+1×(100−1) Now, using distributive property, =(−40×100)+(−1×−40)+(1×100)+(1×(−1)) [∵ a×(b×c)=a×b+a×c]=−4000+40+100−1=−3861
Question 124 (iii)
Evaluate the following, using distributive property. 53×(−9)−(−109)×53
Question 124 (iv)
Evaluate the following, using distributive property. 68×(−17)+(−68)×3
Question 124(ii)
Evaluate the following, using distributive property. (−85)×43+43×(−15)