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Question

Question 124 (i)

Evaluate the following, using distributive property.
39×99

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Solution

39×99=(40+1)×(1001)=40×(1001)+1×(1001)
Now, using distributive property,
=(40×100)+(1×40)+(1×100)+(1×(1)) [ a×(b×c)=a×b+a×c]=4000+40+1001=3861


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