Question 85 (i)
Expand the following, using suitable identities.
(xy+yz)2
We have, (xy+yz)2=(xy)2+(yz)2+2×xy×yz [using the identity, (a+b)2=a2+b2+2ab] =x2y2+y2z2+2xy2z
Question 85 (xv)
(0.9p−0.5q)2
Question 85 (xii)
(x2+y2)(x2−y2)
Question 85 (xiv)
(7x+5)2