I-F of dydx-2xy-e-x2 is-

The correct option is C e^x^2 dydx+2xy=e^ x^2 IF=e^∫ P(n)dx=e^2∫ ndx=e^2x^2/_2=e^x^2 ...

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Integration as Antiderivative

I.F of dydx...

Question

I.F of $\frac{d y}{d x} + 2 x y = e^{- x^{2}}$ is:

2 x

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x^{2}

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e^{x^{2}}

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e^{- x^{2}}

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\frac{d y}{d x} + \frac{4 x}{x^{2} + 1} y = \frac{1}{{(x^{2} + 1)}^{2}}

f : R \to R

f (x) = \frac{e^{x^{2}} - e^{{- x}^{2}}}{e^{x^{2}} + e^{{- x}^{2}}}

f : R \to R

f (x) = \frac{e^{x^{2}} - e^{- x^{2}}}{e^{x^{2}} + e^{{- x}^{2}}},

\frac{d y}{d x} + 2 x y = e^{- x^{2}}

\frac{d y}{d x} + \frac{y}{x} = x^{2}

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