I-F of dydx-4xx2-1y-1 x2-1 2 is-

The correct option is C (x^2+1)^2 I.F = e^∫ P(x)dx =e ^∫4x1+x^2dx =e ^2∫2x1+x^2dx =e^2 log(x^2+1)=e^log(x^2+1)^2 ⇒ I.F = (1+x^2)^ ...

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Theorems on Integration

I.F of dydx...

Question

I.F of $\frac{d y}{d x} + \frac{4 x}{x^{2} + 1} y = \frac{1}{{(x^{2} + 1)}^{2}}$ is:

x^{2} + 1

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\frac{1}{x^{2} + 1}

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(x^{2} + 1)^{2}

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\frac{1}{{(x^{2} + 1)}^{2}}

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