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Byju's Answer
Standard XII
Mathematics
Integrating Factor
I.F of dy/d...
Question
I.F of
d
y
d
x
+
x
sin
2
y
=
x
3
cos
2
y
is:
A
t
a
n
y
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B
e
tan
y
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C
e
s
˙
m
y
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D
e
x
2
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Solution
The correct option is
D
e
x
2
Given the differential equation as
d
y
d
x
+
x
s
i
n
2
y
=
x
3
c
o
s
2
y
On dividing
c
o
s
2
y
on both sides
s
e
c
2
y
d
y
d
x
+
x
×
s
e
c
2
y
×
(
2
s
i
n
y
c
o
s
y
)
=
x
3
s
e
c
2
y
d
y
d
x
+
2
x
t
a
n
y
=
x
3
Let
t
a
n
y
=
P
On differentiating once,
s
e
c
2
y
d
y
d
x
=
d
P
d
x
............(substitute the above values to given D.E)
⇒
d
P
d
x
+
2
x
P
=
x
3
This is in the form of linear differential equation as
d
y
d
x
+
p
(
X
)
y
=
q
(
X
)
.
Then the solution of the equation is
y
×
u
(
x
)
=
(
∫
(
u
(
x
)
×
q
(
x
)
d
x
)
+
C
where
u
(
x
)
=
e
∫
(
p
(
x
)
d
x
)
which is the integration factor of the equation.
⇒
On comparing the given equation with general equation.
P
(
x
)
=
2
x
,
q
(
x
)
=
x
3
∴
I
n
t
e
g
r
a
t
i
n
g
f
a
c
t
o
r
=
e
∫
(
2
x
d
x
)
=
e
x
2
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Q.
Linear form of
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