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Question

I.F of (1+x3)dydx+3x2y=sin2x:

A
1+x3
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B
11+x3
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C
3x2
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D
1x3
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Solution

The correct option is A 1+x3
dydx+3x21+x3y=sin2x1+x3

I.F=eP(x)dx
=e3x21+x3dx
=elog(1+x3)
I.F=1+x3

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