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Question

I.F of (x3+5)dydx+3x2y=cos2x is:

A
e5+x3
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B
5+x3
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C
log(5+x3)
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D
3x25+x3
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Solution

The correct option is C 5+x3
y1+3x2 yx3+5=cos 2xx3+5
P(x)=3x 2x3+5 [t=x3+5]
P(n)dn= 3x 2x3+5dn= dtt=log(t)=log(x3+5)
I.F=eP(n)dn=elog(x3+5)=x3+5


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