Question

$If$ the area of minor sector of a circle with radius 11.2 cm is $49.28c{m}^2$, find the measure of the angle made by the arc.

Answer 1

Area of a sector of a circle of radius 'r' and angle $\theta =\frac{\theta }{360}\pi r^2$
So, $49.28=\frac{\theta }{360}\times \frac{22}{7}\times 11.2\times 11.2$

$\theta ={45}^0$