Question

Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube:
243

Answer 1

243
Prime factors of $243=3\times 3\times 3\times 3\times 3$
Here 3 does not appear in 3’sgroup.
Therefore, 243 must be multiplied by 3 to make it a perfect cube.
$\begin{array}{cc}3& 243\\ 3& 81\\ 3& 27\\ 3& 9\\ 3& 3\\ & 1\end{array}$