Question

Find the probability of the pointer stopping on $D$ from the given figure.

Answer 1

In the spinning wheel, there are five regions $A,A,B,C,D$.

So, total no of outcomes $=5$.

Out of these five outcomes, the pointer to stop at $D$ will occur only once per spin.

So, no. of favorable outcomes $=1$

Therefore, probability of the pointer stopping on $D=\frac{\text{No. of favorable outcomes}}{\text{Total no. of outcomes}}$

$=\frac{1}{5}$