(i) The given quadric equation is
, and roots are real and equal.
Then, find the value of k.
Here, .
As we know that
Putting the values of .
The given equation will have real and equal roots, if D = 0
Thus,
Therefore, the value of k is 0 or 1.
Now, for k = 0, the equation becomes
for k = 1, the equation becomes
Hence, the roots of the equation are .
(ii) x
2 + kx + 16 = 0
It is given that the quadratic equation has equal roots.
Therefore, Discriminant is equal to zero.
Hence, the values of k is ±8.
Now,
For k = 8,
The equation becomes
x
2 + 8x + 16 = 0
⇒ (x + 4)
2 = 0
⇒ x = −4
For k = −8,
The equation becomes
x
2 − 8x + 16 = 0
⇒ (x − 4)
2 = 0
⇒ x = 4
Hence, the roots of the equation so obtained are 4 and −4.