Question

I. Formation of $A$ has proceeded with racemisation.
II. Formation of $B$ has proceeded with inversion.
Select the correct statement:

• A. I and II
• B. Only I
• C. Only III
• D. None of these

Answer 1

The correct option is A I and II

$S_{N}1$ reaction proceed through formation of carbocation which can form a pair of enantiomers. Thus, recemisation takes place (statement I). $S_{N}2$ reaction takes place forming pantavalent intermediate which loses $C{l}^{-}$ giving inverted alcohol. (Statement II) Hence, statement I and II both are correct.