I- 15-x-9-x-11 -xII- -y-4-5 -y-12-1-y

The correct option is D x gt; yEquation I 15/x + 9/x = 11 √(x) 15 + 9/√(x) = 11 √(x) 24 = 11x ∴ x = 24/11 = 2.18 Equation II √(y)/4 + 5 √(y)/12 = 1/√(y) ⇒3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Quantitative Aptitude

Equations

I. 15/x+9/x=1...

Question

I. $\frac{15}{x} + \frac{9}{x} = 11 \sqrt{x}$
II. $\frac{\sqrt{y}}{4} + \frac{5 \sqrt{y}}{12} = \frac{1}{\sqrt{y}}$

x > y

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x \geq y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x < y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x \leq y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = y

or the relationship cannot be established

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x > y$
Equation I
$\frac{15}{x} + \frac{9}{x} = 11 \sqrt{x}$
$\frac{15 + 9}{\sqrt{x}} = 11 \sqrt{x}$
$24 = 11 x$
$∴ x = \frac{24}{11} = 2.18$
Equation II
$\frac{\sqrt{y}}{4} + \frac{5 \sqrt{y}}{12} = \frac{1}{\sqrt{y}}$
$\Rightarrow \frac{3 \sqrt{y} + 5 \sqrt{y}}{12} = \frac{1}{\sqrt{y}}$
$8 y = 12 \Rightarrow y = 1.5$
Hence, x > y

Suggest Corrections

Similar questions

Q. The projection of line

3 x - y + 2 z - 1 = 0 = x + 2 y - z - 2

on the plane

3 x + 2 y + z = 0

Solve the following:

(i) x + 3 = 11; (ii) y − 9 = 21; (iii) 10 = z + 3; (iv) ; (v) 10x = 30; (vi) ;

(vii) ; (viii) ; (ix) 8x − 8 = 48; (x) ; (xi) ; (xii) ;

(xiii) 3 (x + 6) = 24; (xiv) ; (xv) 3(x + 2) − 2(x − 1) = 7.

Q. Solve the following equations.
(1) 17(x+4) + 8(x+6) = 11(x+5) +15(x+3)

(2)

\frac{3 y}{2}

\frac{y + 4}{4}

= 5−

\frac{y - 2}{4}

(3) 5(1−2x) = 9(1−x)

Q. Solve the following pair of equations:

\frac{1}{x} + \frac{3}{y} = 1

\frac{6}{x} - \frac{12}{y} = 2

(Where

x \neq 0, y \neq 0)

Verify the property: $x \times (y \times z) = (x \times y) \times z b y t a k i n g :$

(i) $x = \frac{- 7}{3}, y = \frac{12}{5}, z = \frac{4}{9}$

(ii) $x = 0, y = \frac{- 3}{5}, z = \frac{- 9}{4}$

(iii) $x = \frac{1}{2}, y = \frac{5}{- 4}, z = \frac{- 7}{5}$

(iv) $x = \frac{5}{7}, y = \frac{- 12}{13}, z = \frac{- 7}{18}$

Join BYJU'S Learning Program

I. 15x+9x=11√x II. √y4+5√y12=1√y

The correct option is A x>yEquation I 15x+9x=11√x 15+9√x=11√x 24=11x ∴x=2411=2.18 Equation II √y4+5√y12=1√y ⇒3√y+5√y12=1√y 8y=12⇒y=1.5 Hence, x > y

I. $\frac{15}{x} + \frac{9}{x} = 11 \sqrt{x}$
II. $\frac{\sqrt{y}}{4} + \frac{5 \sqrt{y}}{12} = \frac{1}{\sqrt{y}}$