Question

(i) Given that HCF (306, 657) = 9, find LCM (306, 657).

(ii) Write the smallest number which is divisible by both 306 and 657.

Answer 1

(i) ​

GIVEN: HCF of two numbers 306 and 657 is 9.

TO FIND: L.C.M of number

We know that,

(ii) The smallest number divisible by both 306 and 657 is the LCM of 306 and 657.

306 = 2 × 3 × 3 × 17

657 = 3 × 3 × 73

Therefore, LCM of 306 and 657 is 2 × 3 × 3 × 17 × 73 = 22,338

Hence, the smallest number which is divisible by both 306 and 657 is 22,338.