Question

I got 1 equation 12root3 to the power x = 18 factorial find x how to find exact value how to find

Answer 1

$$\begin{gathered} \mathrm{Hi}, \\ {\left(12\sqrt{3}\right)}^{\mathrm{x}}=18!=18\times 17\times ...\times 3\times 2\times 1 \\ \mathrm{Taking}\log , \\ \mathrm{xlog}12\sqrt{3}=\log 18+\log 17+....+\log 2+\log 1 \\ \mathrm{x}=\frac{\log 18+\log 17+....+\log 2+\log 1}{\log 12+\log {\left(3\right)}^{{\displaystyle \frac{1}{2}}}} \\ \mathrm{Put}\mathrm{the}\mathrm{values}\mathrm{of}\log \mathrm{from}\log \mathrm{table}\mathrm{for}\mathrm{your}\mathrm{practice}\mathrm{an}\mathrm{calculate}\mathrm{the} \\ \mathrm{same}. \\ \mathrm{Regards} \end{gathered}$$