I have doubt with question no 2 from ex 3.1 . In this question the equation 3x+6y=3900, x+3y=1300 if I divide first equation by 3 I get x+2y=1300. So how it possible that x+3y=1300 and x+2y=1300 both rhs is same but not LHS. Please explain this question

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Solution

Actually the question is

Actually the question is
* The coach of a cricket team buys 3 bats and 6 balls for Rs.3900. Later she buys another bat and two more balls of same kind for Rs.1300. Represent this situation algebraically and geometrically.

Ans..

Bat =x

Ball =y

3x+6y=3900

x+2y=1300

By dividing first equation by 3 , we get exactly the same equation 2

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Q. Question 2
The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

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Q. Question 9 (i)
Solve the following pairs of equation

x + y = 3.3, \frac{0.6}{3 x - 2 y} = - 1, 3 x - 2 y \neq 0

Q. How do I find

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 2 - 1 & 3 & 0 0 & - 2 & 1 \end{matrix} ⎤ ⎥ ⎦ = | A | = ?

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