$I . H C l O I I . X e F_{2}$
$I I I . S O_{4}^{2 -} I V . X e O F_{4}$
For the given molecule, the increasing order of lone pairs in the central atoms follow the order:

I < I I < I I I < I V

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I V < I I < I I I < I

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I I < I V < I < I I I

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I I I < I V < I < I I

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Solution

The correct option is D $I I I < I V < I < I I$
$I . H C l O or H O C l$
It has two lone pair on central atom $O$ .

$I I . X e F_{2}$
It has three lone pair on central atom $X e$ .

$I I I . S O_{4}^{2 -}$
It has zero lone pair on central atom $S$ .

$I V . X e O F_{4}$
It has one lone pair on central atom $X e$ .

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I. HClO II. XeF2 III. SO2−4 IV. XeOF4 For the given molecule, the increasing order of lone pairs in the central atoms follow the order:

The correct option is D III<IV<I<III. HClO or HOCl It has two lone pair on central atom O. II. XeF2 It has three lone pair on central atom Xe. III. SO2−4 It has zero lone pair on central atom S. IV. XeOF4 It has one lone pair on central atom Xe.

$I . H C l O I I . X e F_{2}$
$I I I . S O_{4}^{2 -} I V . X e O F_{4}$
For the given molecule, the increasing order of lone pairs in the central atoms follow the order: