(i) If $150$ cc of gas A contains X molecules, how many molecules of gas B will be present in $75$ cc of B?
The gases A and B are under the same conditions of temperature and pressure.
(ii) Name the law on which the given problem is based.

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Solution

(i) For an ideal gas
$V \propto n o r \frac{V_{A}}{n_{A}} = \frac{V_{B}}{n_{B}}$
Therefore, $n_{B} = V_{B} \times \frac{n_{A}}{V_{A}} = 75 \times \frac{X}{150} = \frac{X}{2}$
(ii) It is based on Ideal gas law: $P V = n R T$

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(i) If 150 cc of gas A contains X molecules, how many molecules of gas B will be present in 75 cc of B?The gases A and B are under the same conditions of temperature and pressure.(ii) Name the law on which the given problem is based.

(i) For an ideal gas V∝nor VAnA=VBnBTherefore, nB=VB×nAVA=75×X150=X2(ii) It is based on Ideal gas law: PV=nRT

(i) If $150$ cc of gas A contains X molecules, how many molecules of gas B will be present in $75$ cc of B?
The gases A and B are under the same conditions of temperature and pressure.
(ii) Name the law on which the given problem is based.

(i) For an ideal gas
$V \propto n o r \frac{V_{A}}{n_{A}} = \frac{V_{B}}{n_{B}}$
Therefore, $n_{B} = V_{B} \times \frac{n_{A}}{V_{A}} = 75 \times \frac{X}{150} = \frac{X}{2}$
(ii) It is based on Ideal gas law: $P V = n R T$