I: If →a=3^i−2^j+^k,→b=2^i−4^j−3^k,→c=−^i+2^j+2^k then →a+→b+→c=4^i−4^j II: If →a=^i−^j+2^k,→b=2^i+3^j+^k,→c=^i−^k, then magnitude of →a+2→b−3→c is √78
A
Only I is true
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B
Only II is true
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C
Both I and II are true
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D
Neither l nor ll are true
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Solution
The correct option is C Both I and II are true Consider Statement I →a+→b+→c =(3i−2j+k)+(2i−4j−3k)+(−i+2j+2k) =(3+2−1)i+(−2−4+2)j+(1−3+2)k =4i−4j Hence statement 1 is true. Consider Statement 2 →a+2→b−3→c =(i−j+2k)+(4i+6j+2k)−(3i−3k) =(1+4−3)i+(−1+6)j+(2+2+3)k =2i+5j+7k |2i+5j+7k| =√4+25+49 =√78 Hence statement 2 is true.