Question

(I) (II)

H - N - - -N - - -N

In hydrogen azide, the bond orders of bonds (I) and (II) are:

• A. (I) $<2$, (II) $>2$
• B. (I) $>2$, (II) $>2$
• C. (I) $>2$, (II) $<2$
• D. (I) $<2$, (II) $<2$

Answer 1

The correct option is A (I) $<2$, (II) $>2$

As in the resonance structure of hydrogen azide, it can be seen than number of bond is $\le 2$ for bond $\left(I\right)$

Hence its bond order will be $<2$

Whereas for bond $\left(II\right)$, number of bond $\ge 2$

Thus its bond order will be $>2$.