Respectively at T 1- T 2 and T 3- The temperatures will be in the order-A- T 1- T 2- T 3B- T 1- T 2- T 3- T 1- T 2- T 3D- T 1- T 2- T 3

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Boyle's Law

respectively ...

Question

$I, I I, I I I$ are three isotherms respectively at $T_{1}, T_{2}$ and $T_{3}$ . The temperatures will be in the order:

T_{1} = T_{2} = T_{3}

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T_{1} < T_{2} < T_{3}

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T_{1} > T_{2} > T_{3}

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T_{1} > T_{2} = T_{3}

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Solution

The correct option is C $T_{1} > T_{2} > T_{3}$
Boyle's law states that at constant temperature, the product of pressure and volume is constant.

When a graph is drawn between pressure and volume at different temperatures, hyperbolas are obtained, called as isotherms.

In this graph, the hyperbola at the top corresponds to the higher temperature and the one at the bottom corresponds to the lower temperature.

So the order of temperature is $T_{1} > T_{2} > T_{3}$

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I,II,III are three isotherms respectively at T1,T2 and T3. The temperatures will be in the order:

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