I In a process 10 gm of ice at -5oC is converted into steam at 100oC- If specific heat of water 1 cal g -1 - C -1- the heat required to rise the temperature of water 10 g from 0 -C to 100 -C-

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Specific Heat Capacity

i In a proces...

Question

(i) In a process 10 gm of ice at $- 5^{o} C$ is converted into steam at $100^{o} C$ . If specific heat of water 1 cal $g^{- 1}$ $^{\circ} C^{- 1}$ , the heat required to rise the temperature of water 10 g from $0^{\circ} C$ to $100^{\circ} C$ .

100 c a l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1000 c a l

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10^{4}

cal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10^{5}

cal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1000 c a l$
Given , $c = 1 c a l / g -^{o} C$
$m = 10 g$
Heat required to heat up the water at $100^{o} C$ from $0^{o} C$ , from the definition of specific heat ,
$Q = m c (100 - 0) = 10 \times 1 \times 100 = 1000 c a l$ ,

Suggest Corrections

Similar questions

Q. In a process, 10 gm of ice at

- 5^{o} C

is converted into steam at

100^{o} C

.If latent heat of fusion of ice is 80 cal

g^{- 1}

, then the amount of heat required to convert 10 g of ice at

0^{\circ} C

into 10 g of water at same temperature is :

Q. The amount of heat required to convert 1 g of ice (specific 0.5 cal at

g^{- 1 o} C^{- 1}

) at

- 10^{0} C

to steam at

100

^{\circ} C

is ___________.

[ Given: Latent heat of ice is

80 C a l / g m,

Latent heat of steam is

540 C a l / g m

, Specific heat of water is

1 C a l / g m / C

]

Q. In a process, 10 g of ice at

- 5^{o} C

is converted into the steam at

100^{o} C

. If specific heat of water

1 c a l g^{- 1}^{o} C^{- 1}

; the heat required to raise the temperature of 10 g water from

0^{o} C

100^{o} C

is :

Q. The heat required (in

c a l

) to change 10 g ice at

0^{o} C

to steam at

100^{o} C

is
( Heat of fusion and heat of vaporization for

H_{2} O

are 80 cal/g and 540 cal/g respectively. Specific heat of water is 1 cal/g)

Q. 10 g ice at %%0^{\circ} C

i s c o n v e r t e d i n t o s t e a m a t

100^{\circ} C

. F i n d t o t a l h e a t r e q u i r e d (

L_f = 80 cal/G

,

S_w = 1 cal/g ^{\circ} C

, L_{v} = 540 c a l / g

)

Join BYJU'S Learning Program

(i) In a process 10 gm of ice at −5oC is converted into steam at 100oC. If specific heat of water 1 cal g−1∘C−1, the heat required to rise the temperature of water 10 g from 0∘C to 100∘C.

The correct option is B 1000calGiven , c=1cal/g−oCm=10gHeat required to heat up the water at 100oC from 0oC , from the definition of specific heat , Q=mc(100−0)=10×1×100=1000cal ,

(i) In a process 10 gm of ice at $- 5^{o} C$ is converted into steam at $100^{o} C$ . If specific heat of water 1 cal $g^{- 1}$ $^{\circ} C^{- 1}$ , the heat required to rise the temperature of water 10 g from $0^{\circ} C$ to $100^{\circ} C$ .

The correct option is B $1000 c a l$
Given , $c = 1 c a l / g -^{o} C$
$m = 10 g$
Heat required to heat up the water at $100^{o} C$ from $0^{o} C$ , from the definition of specific heat ,
$Q = m c (100 - 0) = 10 \times 1 \times 100 = 1000 c a l$ ,