Question

i\\In the figure, $Q$ is the centre of the circle
and $PM$ and $PM$ are tangents to the circle.
If $\angle MPN={40}^{\circ }.$ find $\angle MQN.$

Answer 1

R.E.F. Image.

$\sum$ angles of quadrilateral = ${360}^{\circ }$

$40+90+90+Q={360}^{\circ }$

$Q={140}^{\circ }=\angle MQN$