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Triangles on the Same Base and between the Same Parallels

i In the give...

Question

Question 11 (i)
In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that:

(i) ar (ACB) = ar (ACF)

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Solution

$Δ A C B a n d Δ A C F$ lie on the same base AC and are between the same parallels AC and BF.
$\Rightarrow A r e a (Δ A C B) = A r e a (Δ A C F)$

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Similar questions

Q. Question 11 (i)
In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that:

(i) ar (ACB) = ar (ACF)

In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that

(i) ar (ACB) = ar (ACF)

(ii) ar (AEDF) = ar (ABCDE)

Question 11 (ii)
In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that:

(ii) ar(AEDF) = ar(ABCDE)

A B C D E

is a pentagon. A line through

B

A C

D C

F

. Show that
(i)

a r (A C B) = a r (A C F)

a r (A E D F) = a r (A B C D E)

Q. In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that:

a r e a (A E D F) = a r e a (A B C D E)

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Triangles on the Same Base and between the Same Parallels

Standard IX Mathematics

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