I- ion react with iodine in aqueous solution to form I3- ion .When 1L of solution containing 1mole of KI and 0.25 mol of I2 was reacted with excess of AgNO3 ,0.80 mol of yellow precipitate was formed.The stability constant of. I3- ion is
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Solution
Keq=[I 3]/[I 2][I -] =O.80/(0.80)(0.20) =1/0.20 =5 This happens because of the following reaction- 3KI +3AgNo3 ------>3AgI + 3kNo3 when kI react with AgNo 3 it gives yellow precipitate of AgI.