CameraIcon

SearchIcon

MyQuestionIcon

630

You visited us 630 times! Enjoying our articles? Unlock Full Access!

Electrophile

I- ion react ...

Question

I- ion react with iodine in aqueous solution to form I3- ion .When 1L of solution containing 1mole of KI and 0.25 mol of I2 was reacted with excess of AgNO3 ,0.80 mol of yellow precipitate was formed.The stability constant of. I3- ion is

Open in App

Solution

Keq=[I ₃]/[I ₂][I ^-]
=O.80/(0.80)(0.20)
=1/0.20
=5
This happens because of the following reaction-
3KI +3AgNo_{3 ^------>}3AgI + 3kNo₃ when kI _react with AgNo₃ it gives yellow precipitate of AgI.

Suggest Corrections

thumbs-up

1

Similar questions

I_{2} + I^{-} ⇌ I_{3}^{-}

This reaction is set-up in aqueous medium. We start with one mole of

I_{2}

0.5 m o l

I^{-}

1 L

flask. After equilibrium is reached, excess of

A g N O_{3}

0.25 m o l

of yellow precipitate. Equilibrium constant is

Q. Assertion :No yellow precipitate is formed when an excess of a more concentrated

(6

)

K I

is added to a solution containing

P b^{2 +}

ions. Reason: Yellow precipitate of

P b l_{2}

does not dissolve in excess of dilute solution of

K I

.

Q. An aqueous solution containing

0.10 g K I O_{3} (formula weight = 214.0 g / m o l)

was treated with an excess of

K I

solution. The solution was acidified with

H C l .

I_{2}

55 m L

of thiosulphate solution to decolourise the blue starch-iodine complex. Calculate molarity of the sodium thiosulphate solution.

State True or False.

Lead (II) ions react with KI to form yellow precipitate of

P b I_{2}

.

Q. When dilute aqueous solution of

A g N O_{3}

(excess) is added to

K I

solution, positively charged sol particles of

A g I

are formed due to adsorption of ion :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Attacking Species

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon