I is moment of inertia of a thin square plate about an axis passing through opposite comers of plate. The moment of inertia of same plate about an axis perpendicular to the plane of plate and passing through its center is.

\frac{I}{2}

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I \sqrt{2}

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\sqrt{I 2}

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Solution

The correct option is D 2I
We have,
The moment of inertia is

$I_{A D} = I_{B C} = I$

Now, by using perpendicular axis theorem
for

$I_{A D} + I_{B C} = I_{0}$

$2 I = I_{0}$

Hence, the moment of inertia is $2 I$

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I is moment of inertia of a thin square plate about an axis passing through opposite comers of plate. The moment of inertia of same plate about an axis perpendicular to the plane of plate and passing through its center is.

The correct option is D 2IWe have,The moment of inertia is IAD=IBC=I Now, by using perpendicular axis theoremfor IAD+IBC=I0 2I=I0 Hence, the moment of inertia is 2I

The correct option is D 2I
We have,
The moment of inertia is

$I_{A D} = I_{B C} = I$

Now, by using perpendicular axis theorem
for

$I_{A D} + I_{B C} = I_{0}$

$2 I = I_{0}$

Hence, the moment of inertia is $2 I$