I is the incenter of a triangle ABC in which - A - 80 - - BIC -

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Construction of 30, 60, 90 and 120 Degree Angles

I is the ince...

Question

$I$ is the incenter of a triangle $A B C$ in which $∠ A = 80^{\circ} .$ $∠ B I C =$

120^{\circ}

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110^{\circ}

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125^{\circ}

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130^{\circ}

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Solution

The correct option is D $130^{\circ}$
As we know incentre is a meet point of all the angle bisectors

then $∠ B I C = 90 ° + ∠ A / 2$

$∠ B I C = 90 ° + (80 ° / 2)$

$∠ B I C = 130 °$

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Similar questions

In a triangle ABC, ∠B = 60° and ∠C = 80°. Suppose the bisector of ∠B and ∠C meet at I. Find ∠BIC.

Q. If

I

is the incentre of triangle

A B C

and

A I

when produced meets the circumcircle of triangle

A B C

in point

D

. If

∠ B A C = 66^{\circ}

and

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. Calculate

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\frac{5}{4}

as a percent is

(a) 80%
(b) 125%
(c) 120%
(d) 130%

The median for the data is

$\begin{matrix} IQ & 60 - 70 & 70 - 80 & 80 - 90 & 90 - 100 & 100 - 110 & 110 - 120 & 120 - 130 No. of pupils & 2 & 3 & 5 & 16 & 14 & 13 & 7 \end{matrix}$

Q. Calculate the mean of the following frequency distribution.

Class	$90 - 100$	$100 - 110$	$110 - 120$	$120 - 130$	$130 - 140$
Frequency	$18$	$78$	$80$	$100$	$72$

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I is the incenter of a triangle ABC in which ∠A=80∘. ∠BIC=

The correct option is D 130∘As we know incentre is a meet point of all the angle bisectorsthen ∠BIC=90°+∠A/2 ∠BIC=90°+(80°/2) ∠BIC=130°

$I$ is the incenter of a triangle $A B C$ in which $∠ A = 80^{\circ} .$ $∠ B I C =$

The correct option is D $130^{\circ}$
As we know incentre is a meet point of all the angle bisectors

then $∠ B I C = 90 ° + ∠ A / 2$

$∠ B I C = 90 ° + (80 ° / 2)$

$∠ B I C = 130 °$