Question

I is the moment of inertia of a thin circular ring about an axis perpendicular to the plane of ring and passing through its centre . The same ring is folded into 2 turns coil. the moment of inertia of circular coil about an axis perpendicular to the plane of coil and passing through its centre is? ( In terms of I)

Answer 1

Mass remains same but radius decreases to half.

Thus, m.(r/2)^2 = I/4

This new moment of inertia is I/4