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Question

Question 8 (i)
Justify whether it is true to say that the following are the nth terms of an AP.

2n – 3

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Solution

Yes.
Here, an = 2n – 3
Put n = 1, a1 = 2(1) - 3 = -1
Put n = 2, a2 = 2 (2) - 3 = 1
Put n = 3, a3 = 2(3) - 3 = 3
Put n = 4, a4 = 2(4) - 3 = 5
The numbers are;
- 1, 1, 3 ....
Here, a2a1=1(1)=1+1=2
a3a2=31=2
a4a3=53=2
a2a1=a3a2=a4a3=
Hence, 2n - 3 is the nth term of an AP.

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