I: Let ¯¯¯¯α=(x+4y)a+(2x+y+1)b, ¯¯¯β=y−2x+2)a+(2x−3y−1)b where a and b are nonzero, noncollinear vectors if 3 ¯¯¯¯α=2¯¯¯β=x=2,y=−1.
II: Let D,E,F be the middle points of the sides BC.CA,AB respectively of ΔABC then AD+BE+CF=0.
A
Only I is true
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B
Only II is true
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C
Both I and II are true
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D
Neither I nor II are true
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Solution
The correct option is C Both I and II are true I 3→α=2→β 3((x+4y)a+(2x+y+1)b)=2((y−2x+2)a+(2x−3y−1)b) (3x+12y)a+(6x+3y+3)b)=(2y−4x+4)a+(4x−6y−2)b) 3x+12y=2y−4x+4 ( a & b are not collinear ) 7x+10y=4 --(1) 6x+3y+3=4x−6y−2 2x+9y=−5 --(2) x=2y=−1 AD+BE+CF=→D+→E+→F−→A−→B−→C =→a+→b+→c−→a−→b−→c =0