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Question

I: Let ¯¯¯¯α=(x+4y)a+(2x+y+1)b, ¯¯¯β=y2x+2)a+(2x3y1)b where a and b are nonzero, noncollinear vectors if 3 ¯¯¯¯α=2¯¯¯β=x=2,y=1.


II: Let D,E,F be the middle points of the sides BC.CA,AB respectively of ΔABC then AD+BE+CF=0.

A
Only I is true
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B
Only II is true
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C
Both I and II are true
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D
Neither I nor II are true
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Solution

The correct option is C Both I and II are true
I 3α=2β
3((x+4y)a+(2x+y+1)b)=2((y2x+2)a+(2x3y1)b)
(3x+12y)a+(6x+3y+3)b)=(2y4x+4)a+(4x6y2)b)
3x+12y=2y4x+4 ( a & b are not collinear )
7x+10y=4 --(1)
6x+3y+3=4x6y2
2x+9y=5 --(2)
x=2 y=1
AD+BE+CF=D+E+FABC
=a+b+cabc
=0

55745_34777_ans.JPG

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