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Question

I :f(x)=logax(x>0) is an increasing function if a>1
II :f(x)=logax(x>0) is a decreasing function if 0<a<1
Which of the above statements are true ?

A
only I
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B
only II
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C
both I and II
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D
neither I nor II
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Solution

The correct option is C both I and II
(I) f(x)=logxloga
f(x)=1xloga
If f(x)>0 than loga>0
Therefore a>1
(II) f(x)=logxloga
f(x)=1xloga
If f(x)<0 than loga<0
So 0<a<1

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