CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

I :f(x)=logax(x>0) is an increasing function if a>1
II :f(x)=logax(x>0) is a decreasing function if 0<a<1
Which of the above statements are true ?

A
only I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
only II
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
both I and II
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
neither I nor II
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C both I and II
(I) f(x)=logxloga
f(x)=1xloga
If f(x)>0 than loga>0
Therefore a>1
(II) f(x)=logxloga
f(x)=1xloga
If f(x)<0 than loga<0
So 0<a<1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Monotonicity
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon