I- N 2 g -2 O 2 g - 2 NO 2 g - - H I -16-18 kcalII- N 2 g -2 O 2 g - N 2 O 4 g - - H II -2-31 kcalBased on the above reactions-A- NO 2 is more stable than N 2 O 4 at low temperatureB- N 2 O 4 is more stable than NO 2 at low temperatureC- Both are equally stable at low temperatureD- None of the above

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Types of Catalysis

I. N 2 g +2 O...

Question

$I . N_{2} (g) + 2 O_{2} (g) ⟶ 2 N O_{2} (g); Δ H_{I} = 16.18 kcal$
$I I . N_{2} (g) + 2 O_{2} (g) ⟶ N_{2} O_{4} (g); Δ H_{I I} = 2.31 kcal$

Based on the above reactions:

N O_{2}

is more stable than

N_{2} O_{4}

at low temperature

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N_{2} O_{4}

is more stable than

N O_{2}

at low temperature

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Both are equally stable at low temperature

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None of the above

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25^{\circ} C

N_{2} (g) + 2 O_{2} (g) \to 2 N O_{2} (g); △ H = 16.18 k c a l

N_{2} (g) + 2 O_{2} (g) \to N_{2} O_{4} (g); △ H = 2.31 k c a l

N O_{2}

N_{2} O_{4}

N O_{2}

25^{\circ} C

(13.87 k c a l, N_{2} O_{4}

N_{2} (g) + 2 O_{2} (g) \to 2 N O_{4} (g), Δ H_{I} = 16.18 k c a l

N_{2} (g) + 2 O_{2} (g) \to N_{2} O_{4} (g), Δ H_{I I} = 2.31 k c a l

N O_{2} (g)

N_{2} O_{4} (g)

N O_{2}

C O_{2}

N O_{2}

N_{2} O_{4}

For the reaction $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), Δ H = - v e$ . The formation of $N H_{3} (g)$ is favored a

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

N_{2} O_{4}

x

N_{2} O_{4}

N O_{2}

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