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Van't Hoff Factor

i. NaNO3 ...

Question

$i .$ $N a N O_{3}$
$i i .$ $B a {C l}_{2}$
$i i i .$ $K_{3} [F e {(C N)}_{6}]$
$i v .$ $C_{6} H_{12} O_{6}$
Increasing order of Van't Hoff factor is:

(i v) < (i i) < (i) < (i i i)

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(i v) > (i i) > (i) > (i i i)

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(i v) < (i i i) < (i i) < (i)

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(i v) < (i) < (i i) < (i i i)

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Solution

The correct option is A $(i v) < (i) < (i i) < (i i i)$
More no of ions, more is the factor so
$C_{6} H_{12} O_{6}; i = 1 < N a N O_{3}; i = 2 < B a {C l}_{2}; i = 3 < K_{3} [F e {(C N)}_{6}]; i = 4$

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