3x + 2y = 5 ; 2x - 3y = 7
3x + 2y - 5 = 0 ; 2x - 3y - 7 = 0
Comparing these equations with
a1x+b1y+c1=0
a2x+b2y+c2=0
We get
a1=3,b1=2, and c1=−5
a2=2,b2=−3 and c2=−7
a1a2=32
b1b2=−23 and
c1c2=57
Hence, a1a2≠b1b2
These linear equations are intersecting each other at one point and thus have only one possible solution. Hence, the pair of linear equations are consistent.