II- p- 2-12 p-35-1211II- -q- 2-3 q-2-01

The correct option is B p ≤ q(I) p^2 + 12p + 35 = 0 ⇒ p^2 + 7p + 5p + 35 = 0 ⇒ p(p + 7) + 5(p + 7) = 0 ⇒ (p +7) (p + 5) = 0 ⇒ p = 5 or 7 (II) 2q^2 + 22q ...

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Quantitative Aptitude

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II. p∧ 2-12 p...

Question

$I . p^{2} - 12 p + 35 = - 12 I I . q^{2} - 3 q + 2 = 0$

p < q

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p > q

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\geq

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p = q

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Solution

The correct option is C p $\leq$ q
$(I) p^{2} + 12 p + 35 = 0 \Rightarrow p^{2} + 7 p + 5 p + 35 = 0 \Rightarrow p (p + 7) + 5 (p + 7) = 0 \Rightarrow (p - + 7) (p + 5) = 0 \Rightarrow p = - 5 o r - 7 (I I) 2 q^{2} + 22 q + 56 = 0 \Rightarrow 2 q^{2} + 14 q + 8 q + 56 = 0 \Rightarrow 2 q (q + 7) + 8 (q + 7) = 0 \Rightarrow (q + 7) (2 q + 8) = 0 \Rightarrow q = - 7 o r - 4$
Obviously, $p \leq q$

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I.p2−12p+35=−12II.q2−3q+2=0

The correct option is C p ≤ q(I) p2+12p+35=0⇒p2+7p+5p+35=0⇒p(p+7)+5(p+7)=0⇒(p−+7)(p+5)=0⇒p=−5 or −7(II) 2q2+22q+56=0⇒2q2+14q+8q+56=0⇒2q(q+7)+8(q+7)=0⇒(q+7)(2q+8)=0⇒q=−7 or −4 Obviously, p≤q

$I . p^{2} - 12 p + 35 = - 12 I I . q^{2} - 3 q + 2 = 0$