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Question

I.p27p=12II.q23q+2=0

A
p < q
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B
p > q
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C
p q
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D
p q
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E
p = q
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Solution

The correct option is B p > q
(I) p27p=12p24p+12=0p24p3p+12=0p(p4)3(p4)=0(p4)(p3)=0p=3or4(II) q23q+2=0q22q9+2=0q(q2)1(q2)=0(q2)(q1)=0q=1or2Obviously p>q

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