wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

I.p27p=12II.q23q+2=0

A
p < q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
p > q
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
p q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
p q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
p = q
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B p > q
(I) p27p=12p24p+12=0p24p3p+12=0p(p4)3(p4)=0(p4)(p3)=0p=3or4(II) q23q+2=0q22q9+2=0q(q2)1(q2)=0(q2)(q1)=0q=1or2Obviously p>q

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Functions
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon