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B
p > q
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C
p ≤ q
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D
p ≥ q
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E
p = q
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Solution
The correct option is D p ≥ q (I)p2−8p+15=0⇒p2−3p−5p+15=0⇒p(p−3)−5(p−3)=0⇒(p−3)(p−5)=0⇒p=3or5(II)q2−5q=−6⇒q2−5q+6=0⇒q2−3q−2q+6=0⇒q(q−3)−2(q−3)=0⇒q(q−3)(q−2)=0⇒q=3or2Obviously,p≥q.