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Question

I. p28p+15=0II. q25q=6

A
p < q
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B
p > q
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C
p ≤ q
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D
p ≥ q
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E
p = q
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Solution

The correct option is D p ≥ q
(I) p28p+15=0p23p5p+15=0p(p3)5(p3)=0(p3)(p5)=0p=3 or 5(II)q25q=6q25q+6=0q23q2q+6=0q(q3)2(q3)=0q(q3)(q2)=0q=3 or 2Obviously, pq.

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