Question 7 (i) P and Q are respectively the mid-points of sides AB and BC of a triangle ABC and R is the mid-point of AP, show that: (i)ar(PRQ)=12ar(ARC)
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Solution
Construction: Join PQ, RQ and RC.
QP and QR medians of triangles QAB and QAP. ∴ar(ΔQAP)=ar(ΔPBQ) ------- (1) And ∴ar(ΔQAP)=2ar(ΔPQR) --------- (2) From (1) and (2), we get, ⇒ar(ΔPBQ)=2ar(ΔPQR) ------- (3) ⇒ar(ΔARC)=2ar(ΔPQR) ------ (4) ⇒ar(ΔPQR)=12ar(ΔARC) Hence, ar(ΔPQR)=12ar(ΔARC)