Question 5 i Rationalize the denominator of 1-7-

Name: NCERT - Grade 09 - Mathematics - Number Systems - Q23_1
Uploaded: 2022-07-04T10:36:42+05:30
Description: 1/√(7) Multiplying √(7) to nbsp;numerator and denominator, we get, =1 ×√(7)/√(7)×√(7) =√(7)/7 ...

1/√(7) Multiplying √(7) to nbsp;numerator and denominator, we get, =1 ×√(7)/√(7)×√(7) =√(7)/7 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Identities of Mathematical Operations

Question 5 i ...

Question

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

Open in App

Solution

$\frac{1}{\sqrt{7}}$

Multiplying $\sqrt{7}$ to numerator and denominator, we get,

$= \frac{1 \times \sqrt{7}}{\sqrt{7} \times \sqrt{7}}$

$= \frac{\sqrt{7}}{7}$

Suggest Corrections

Similar questions

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

Question 5 (iv)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{7} - 2)}$

Question 5 (ii)
Rationalize the denominator of :
$\frac{1}{(\sqrt{7} - \sqrt{6})}$ .

Question 5 (iv)
Rationalize the denominators of the following:

$\frac{1}{(\sqrt{7} - 2)}$

Join BYJU'S Learning Program

Explore more

Identities of Mathematical Operations

Standard VIII Mathematics

Join BYJU'S Learning Program

Question 5 (i) Rationalize the denominator of 1√7 .

1√7 Multiplying √7 to numerator and denominator, we get, =1×√7√7×√7 =√77

Question 5 (i)
Rationalize the denominator of $\frac{1}{\sqrt{7}}$ .

$\frac{1}{\sqrt{7}}$

Multiplying $\sqrt{7}$ to numerator and denominator, we get,

$= \frac{1 \times \sqrt{7}}{\sqrt{7} \times \sqrt{7}}$

$= \frac{\sqrt{7}}{7}$