I read that
S=Ut+1/2(at)²
Is dimensionally correct and physically wrong.
Could you explain what is the meaning behind
the term 'physically'?

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Solution

Physically, you can not compare distance(S) to Velocity(U), Acceleration(A) and Time(T) as they are different physical quantities. That being said, you can compare S,U,A and T dimensionally as they collectively equate to a dimension of space(S-Distance/Displacement).

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